5x^2-12x+40=0

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Solution for 5x^2-12x+40=0 equation:


Simplifying
5x2 + -12x + 40 = 0

Reorder the terms:
40 + -12x + 5x2 = 0

Solving
40 + -12x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
8 + -2.4x + x2 = 0

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -2.4x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + -2.4x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -2.4x + x2 = 0 + -8
-2.4x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-2.4x + x2 = -8

The x term is -2.4x.  Take half its coefficient (-1.2).
Square it (1.44) and add it to both sides.

Add '1.44' to each side of the equation.
-2.4x + 1.44 + x2 = -8 + 1.44

Reorder the terms:
1.44 + -2.4x + x2 = -8 + 1.44

Combine like terms: -8 + 1.44 = -6.56
1.44 + -2.4x + x2 = -6.56

Factor a perfect square on the left side:
(x + -1.2)(x + -1.2) = -6.56

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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